Table of contents
- 1. Intro to Stats and Collecting Data55m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically1h 45m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables2h 33m
- 6. Normal Distribution and Continuous Random Variables1h 38m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 3m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 12m
- 9. Hypothesis Testing for One Sample1h 1m
- 10. Hypothesis Testing for Two Samples2h 8m
- 11. Correlation48m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 20m
- 14. ANOVA1h 0m
4. Probability
Multiplication Rule: Dependent Events
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What is the probability that a card player draws two aces from a standard deck of 52 cards if they keep the first card after drawing it?
A
0.0035
B
0.0059
C
0.0045
D
0.0044

1
Step 1: Understand the problem. A standard deck of cards has 52 cards, and there are 4 aces in the deck. The player draws two cards sequentially, keeping the first card after drawing it. This means the total number of cards remains 52 for both draws.
Step 2: Calculate the probability of drawing an ace on the first draw. Since there are 4 aces in the deck, the probability is given by \( P(\text{First Ace}) = \frac{4}{52} \).
Step 3: Calculate the probability of drawing an ace on the second draw. Since the first card is kept, the total number of cards remains 52, and there are still 4 aces in the deck. Thus, the probability is \( P(\text{Second Ace}) = \frac{4}{52} \).
Step 4: Multiply the probabilities of the two independent events (drawing an ace on the first draw and drawing an ace on the second draw). The combined probability is \( P(\text{Two Aces}) = P(\text{First Ace}) \times P(\text{Second Ace}) = \frac{4}{52} \times \frac{4}{52} \).
Step 5: Simplify the expression \( \frac{4}{52} \times \frac{4}{52} \) to find the final probability. This will give you the probability of drawing two aces under the given conditions.
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