Table of contents
- 1. Intro to Stats and Collecting Data55m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically1h 45m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables2h 33m
- 6. Normal Distribution and Continuous Random Variables1h 38m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 3m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 12m
- 9. Hypothesis Testing for One Sample1h 1m
- 10. Hypothesis Testing for Two Samples2h 8m
- 11. Correlation48m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 20m
- 14. ANOVA1h 0m
4. Probability
Multiplication Rule: Dependent Events
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
About 15% of people in a town have both a cat and a dog. As 64% of residents have a dog, what is the probability that someone in the town owns a cat, given they have a dog?
A
0.23
B
0.15
C
0.64
D
0.096

1
Step 1: Recognize that this is a conditional probability problem. The formula for conditional probability is P(A|B) = P(A ∩ B) / P(B), where P(A|B) is the probability of event A given event B, P(A ∩ B) is the probability of both events A and B occurring, and P(B) is the probability of event B.
Step 2: Define the events in the problem. Let A represent the event 'a person owns a cat' and B represent the event 'a person owns a dog.' The problem provides P(A ∩ B) = 0.15 (probability of owning both a cat and a dog) and P(B) = 0.64 (probability of owning a dog).
Step 3: Substitute the given values into the conditional probability formula. Using P(A|B) = P(A ∩ B) / P(B), substitute P(A ∩ B) = 0.15 and P(B) = 0.64.
Step 4: Simplify the fraction to calculate P(A|B). This will give the probability that someone owns a cat, given that they own a dog.
Step 5: Interpret the result. The final value represents the likelihood of a person owning a cat if it is already known that they own a dog.
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