Table of contents
- 1. Intro to Stats and Collecting Data55m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically1h 45m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables2h 33m
- 6. Normal Distribution and Continuous Random Variables1h 38m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 3m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 12m
- 9. Hypothesis Testing for One Sample1h 1m
- 10. Hypothesis Testing for Two Samples2h 8m
- 11. Correlation48m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 20m
- 14. ANOVA1h 0m
8. Sampling Distributions & Confidence Intervals: Proportion
Sampling Distribution of Sample Proportion
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
A previous study found that of people preferred drinking Pepsi over Coca Cola. Use a normal distribution to approximate the probability that a random sample of people reveals people or more preferring Pepsi.
A
0.8
B
0.6
C
0
D
1

1
Identify the problem as a binomial distribution problem where n = 100 (sample size) and p = 0.8 (probability of preferring Pepsi).
Use the normal approximation to the binomial distribution. Calculate the mean (μ) and standard deviation (σ) of the distribution using the formulas: μ = np and σ = sqrt(np(1-p)).
Substitute the values into the formulas: μ = 100 * 0.8 and σ = sqrt(100 * 0.8 * 0.2).
Convert the binomial problem to a normal distribution problem by finding the z-score for 60 people preferring Pepsi using the formula: z = (X - μ) / σ, where X is the number of successes (60 in this case).
Use the standard normal distribution table or a calculator to find the probability corresponding to the calculated z-score. This will give the probability of 60 or more people preferring Pepsi.
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