Table of contents
- 1. Intro to Stats and Collecting Data55m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically1h 45m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables2h 33m
- 6. Normal Distribution and Continuous Random Variables1h 38m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 3m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 12m
- 9. Hypothesis Testing for One Sample1h 1m
- 10. Hypothesis Testing for Two Samples2h 8m
- 11. Correlation48m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 20m
- 14. ANOVA1h 0m
6. Normal Distribution and Continuous Random Variables
Standard Normal Distribution
Problem 5.1.51
Textbook Question
Finding Probability In Exercises 47–56, find the indicated probability using the standard normal distribution. If convenient, use technology to find the probability.
P(- 0.89 < z < 0)

1
Step 1: Understand the problem. The goal is to find the probability that the standard normal variable z falls between -0.89 and 0. This involves using the standard normal distribution, which has a mean of 0 and a standard deviation of 1.
Step 2: Recall that the standard normal distribution table (or z-table) provides the cumulative probability from the far left of the distribution up to a given z-value. Alternatively, technology such as a graphing calculator or statistical software can be used to find probabilities.
Step 3: Break the problem into two parts. First, find the cumulative probability for z = 0. From the properties of the standard normal distribution, the cumulative probability for z = 0 is 0.5 (since it is the mean of the distribution).
Step 4: Next, find the cumulative probability for z = -0.89. Use a z-table or technology to determine this value. The z-table will give the cumulative probability from the far left of the distribution up to z = -0.89.
Step 5: Subtract the cumulative probability for z = -0.89 from the cumulative probability for z = 0. This difference represents the probability that z falls between -0.89 and 0. Mathematically, this is expressed as P(-0.89 < z < 0) = P(z < 0) - P(z < -0.89).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Standard Normal Distribution
The standard normal distribution is a special case of the normal distribution with a mean of 0 and a standard deviation of 1. It is represented by the variable 'z', which indicates how many standard deviations an element is from the mean. This distribution is crucial for calculating probabilities and is often used in statistical analysis to standardize scores.
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Z-Scores
A z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It is calculated by subtracting the mean from the value and then dividing by the standard deviation. Z-scores allow for the comparison of scores from different distributions and are essential for finding probabilities in the standard normal distribution.
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Probability Calculation
Probability calculation in the context of the standard normal distribution involves finding the area under the curve between two z-scores. This area represents the likelihood of a value falling within that range. Tools such as z-tables or statistical software can be used to determine these probabilities, making it easier to analyze data and draw conclusions.
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