Table of contents
- 1. Introduction to Statistics53m
- 2. Describing Data with Tables and Graphs2h 1m
- 3. Describing Data Numerically1h 48m
- 4. Probability2h 26m
- 5. Binomial Distribution & Discrete Random Variables2h 55m
- 6. Normal Distribution & Continuous Random Variables1h 48m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 17m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 20m
- 9. Hypothesis Testing for One Sample1h 8m
- 10. Hypothesis Testing for Two Samples2h 8m
- 11. Correlation48m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 30m
- 14. ANOVA1h 4m
7. Sampling Distributions & Confidence Intervals: Mean
Confidence Intervals for Population Mean
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
You want to purchase one of the new Altima. You randomly select 400 dealerships across the United States and find a mean of $25,000. Assume a population standard deviation of $2500. Construct and interpret a 94% confidence interval for the true mean price for the new Nissan Altima.
A
(24992.5, 25007.5); We are 94% confident that the true mean price for the new Nissan Altima falls between $24992.5 and $25007.5.
B
(24882.438, 25117.563); We are 94% confident that the true mean price for the new Nissan Altima falls between $24882.438 and $25117.563.
C
(24764.875, 25235.15); We are 94% confident that the true mean price for the new Nissan Altima falls between $24764.875 and $25235.15.
D
(24529.75, 25470.25); We are 94% confident that the true mean price for the new Nissan Altima falls between $24529.75 and $25470.25.

1
Identify the given values: sample mean (\(\bar{x}\)) is $25,000, population standard deviation (\(\sigma\)) is $2,500, sample size (\(n\)) is 400, and the confidence level is 94%.
Determine the z-score corresponding to a 94% confidence level. Since the confidence level is 94%, the remaining 6% is split equally in the two tails of the normal distribution. Look up the z-score for 3% in a standard normal distribution table or use a calculator to find it.
Calculate the standard error of the mean (SE) using the formula: \(SE = \frac{\sigma}{\sqrt{n}}\), where \(\sigma\) is the population standard deviation and \(n\) is the sample size.
Compute the margin of error (ME) using the formula: \(ME = z \times SE\), where \(z\) is the z-score found in step 2 and \(SE\) is the standard error calculated in step 3.
Construct the confidence interval using the formula: \(\bar{x} \pm ME\), where \(\bar{x}\) is the sample mean and \(ME\) is the margin of error. This will give you the lower and upper bounds of the confidence interval.
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