Table of contents
- 0. Functions4h 53m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation2h 18m
- 4. Derivatives of Exponential & Logarithmic Functions1h 16m
- 5. Applications of Derivatives2h 19m
- 6. Graphical Applications of Derivatives6h 0m
- 7. Antiderivatives & Indefinite Integrals48m
- 8. Definite Integrals4h 36m
- 9. Graphical Applications of Integrals1h 43m
- 10. Integrals of Inverse, Exponential, & Logarithmic Functions21m
- 11. Techniques of Integration2h 7m
- 12. Trigonometric Functions6h 54m
- Angles29m
- Trigonometric Functions on Right Triangles1h 8m
- Solving Right Triangles23m
- Trigonometric Functions on the Unit Circle1h 19m
- Graphs of Sine & Cosine46m
- Graphs of Other Trigonometric Functions32m
- Trigonometric Identities52m
- Derivatives of Trig Functions42m
- Integrals of Basic Trig Functions28m
- Integrals of Other Trig Functions10m
- 13: Intro to Differential Equations2h 23m
- 14. Sequences & Series1h 53m
- 15. Power Series2h 19m
0. Functions
Piecewise Functions
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Using the piecewise function below, evaluate f(5)

A
B
C
D

1
Step 1: Analyze the piecewise function provided. The function is defined in three parts: (1) f(x) = 2x + 4 for x < 0, (2) f(x) = x^2 for 0 ≤ x < 2, and (3) f(x) = x^3 + 5 for x ≥ 2.
Step 2: Determine which part of the piecewise function applies to the given input x = 5. Since 5 is greater than or equal to 2, the third part of the function, f(x) = x^3 + 5, is applicable.
Step 3: Substitute x = 5 into the applicable part of the function, f(x) = x^3 + 5. This means you will calculate 5^3 + 5.
Step 4: Simplify the expression 5^3 + 5. First, calculate 5^3 (which is 5 multiplied by itself three times), then add 5 to the result.
Step 5: The simplified result will give you the value of f(5).
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